Grade 10, Second Term Examination, ISAN

                                                   ISAN, Kaski

                                        Second Terminal Examination 2072

     (Force, Pressure, Energy, Heat, Light, Classification of elements, Acid base and salt, Some gases, Metals, Classification of plants and animals, Virus, Stimulation and reaction, Cell division, Reproduction, History of earth and atmosphere.)

 

 

 Q.1 a) The acceleration due to gravity on the surface of the earth is 9.8 m/s² . What is its meaning? At what conditions is the gravitational force equal to 6.67* 10^-11N? The mass of the Jupiter is 319 times greater than the mass of the Earth and its radius is 11 times greater than the radius of the earth. If the acceleration due to gravity on the surface is 9.8 m/s², calculate the acceleration due to gravity on the surface of Jupiter.

Ans:

 The acceleration due to gravity on the surface of the earth is 9.8 m/s². It means the velocity of the freely falling body increases by 9.8 m/s in each second on the earth surface.

 When the masses of each body is in unit i.e 1 kg and the distance between their center is also in unit i.e 1 m, then the gravitational force between them is 6.67 * 10^-11 N.

We have given:

Let the mass of earth be M

Let the radius of the earth be R

According to question,

Mass of Jupiter is 319M

Radius of Jupiter is 11R

 

Solution: